A-Level · Mathematics · AQA · Mark scheme decoded
AQA A-Level Mathematics: Circle Coordinate Geometry — mark scheme explained
The short answer
In this section, we will explore the coordinate geometry of circles. This includes understanding and using the equation of a circle in its standard form, completing the square to find the centre and radius, and applying key properties of circles.
The question
Find the equation of a circle with centre (3, -4) and radius 5. [Paraphrased for study — not reproduced from any exam paper.]
Mark scheme, decoded
What each mark is really for — in plain English — and the wording trap that loses it.
- S1
The standard form of the equation of a circle is (x - a) 2 + (y - b) 2 = r 2 .
- S2
Here, the centre (a, b) is (3, -4) and the radius r is 5.
- S3
Substitute these values into the equation: (x - 3) 2 + (y + 4) 2 = 5 2 .
- S4
Simplify the right-hand side: (x - 3) 2 + (y + 4) 2 = 25.
Model answer
Worked through, with each step tagged to the mark it earns.
- S1
The standard form of the equation of a circle is (x - a) 2 + (y - b) 2 = r 2 .
- S2
Here, the centre (a, b) is (3, -4) and the radius r is 5.
- S3
Substitute these values into the equation: (x - 3) 2 + (y + 4) 2 = 5 2 .
- S4
Simplify the right-hand side: (x - 3) 2 + (y + 4) 2 = 25.
Final answer: (x - 3) 2 + (y + 4) 2 = 25
Common mistakes
- Forgetting to complete the square when finding the centre and radius. — Always rewrite the equation in the form (x - a) 2 + (y - b) 2 = r 2 by completing the square for both x and y terms.
- Incorrectly calculating the radius when completing the square. — After completing the square, ensure you take the square root of the constant term on the right-hand side to find the radius.
- Misapplying the property that the angle in a semicircle is a right angle. — Always verify that the triangle is inscribed in a semicircle and that the angle at the circumference is opposite the diameter.
- Forgetting that the perpendicular from the centre to a chord bisects the chord. — Remember that the perpendicular from the centre to a chord always bisects the chord. Use this property to find the length of the chord or its midpoint.
- Incorrectly identifying the relationship between the radius and the tangent. — Always remember that the radius at any point on the circumference is perpendicular to the tangent at that point. Use this property to find angles or distances.
- Failing to check if a given equation represents a circle. — Always verify that the equation can be written in the standard form (x - a) 2 + (y - b) 2 = r 2 . If it cannot, the given equation may represent another conic section.
- Incorrectly calculating the midpoint of a chord. — Double-check your calculations and ensure you correctly apply the midpoint formula: (x 1 + x 2 ) / 2, (y 1 + y 2 ) / 2.
Where the marks go
- Full worked solution (all marking points)3 marks