A-Level · Physics · AQA · Mark scheme decoded

AQA A-Level Physics: Electrical Characteristics and Ohm's Law — mark scheme explained

Machine-verifiedchecked against the AQA A-Level Physics specificationlast verified 2 July 2026

The short answer

In this section, we will explore the electrical characteristics of different components: ohmic conductors, semiconductor diodes, and filament lamps. We will also delve into Ohm’s law and how it applies to these components under constant physical conditions.

The question

A resistor has a resistance of 10 Ω. If a potential difference of 5 V is applied across it, calculate the current flowing through the resistor. [Paraphrased for study — not reproduced from any exam paper.]

Mark scheme, decoded

What each mark is really for — in plain English — and the wording trap that loses it.

  • S1

    Step 1: Identify the given values: R = 10 Ω, V = 5 V.

  • S2

    Step 2: Use Ohm's law to find the current: I = V / R = 5 V / 10 Ω = 0.5 A.

Model answer

Worked through, with each step tagged to the mark it earns.

  1. S1

    Step 1: Identify the given values: R = 10 Ω, V = 5 V.

  2. S2

    Step 2: Use Ohm's law to find the current: I = V / R = 5 V / 10 Ω = 0.5 A.

  3. Final answer: 0.5 A

Common mistakes

  • Assuming all components follow Ohm's law — Understand the specific characteristics of each component: ohmic conductors have a linear I-V relationship, while diodes and filament lamps do not.
  • Confusing the roles of ammeters and voltmeters — Remember that an ideal ammeter has zero resistance and is connected in series, while an ideal voltmeter has infinite resistance and is connected in parallel.
  • Forgetting the effect of temperature on filament lamps — Understand that the resistance of a filament lamp increases with temperature, causing the I-V curve to become less steep (it flattens and bends towards the voltage axis) as the voltage increases.
  • Misinterpreting the forward and reverse bias regions of diodes — Recognize that in forward bias, the current increases exponentially with a small increase in voltage, while in reverse bias, the current remains very low until the breakdown voltage is reached.
  • Incorrectly plotting I-V characteristics — Ensure that the I-V characteristic graph is plotted correctly with the appropriate axis (I on the horizontal or vertical) and that the shape of the curve reflects the component's behavior.
  • Failing to consider constant physical conditions in Ohm's law — Understand that Ohm's law (V = IR) is valid only when the physical conditions (e.g., temperature) remain constant. For components like filament lamps, the resistance changes with temperature.

Where the marks go

  • Full worked solution (all marking points)3 marks

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